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author | kaiwu <kaiwu2004@gmail.com> | 2023-01-19 13:22:25 +0800 |
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committer | kaiwu <kaiwu2004@gmail.com> | 2023-01-19 13:22:25 +0800 |
commit | a5ab1e0bdbb8ccc53199c3783100e971e23a2c7a (patch) | |
tree | 74b7af62257307e1db405f9a87551d795bf3453e /src | |
parent | 492fc08facfd4c46a7176c67d55ddb4947e88ba6 (diff) | |
download | advent-of-code-a5ab1e0bdbb8ccc53199c3783100e971e23a2c7a.tar.gz advent-of-code-a5ab1e0bdbb8ccc53199c3783100e971e23a2c7a.zip |
2015 done
Diffstat (limited to 'src')
-rw-r--r-- | src/2015/day25/README.md | 7 | ||||
-rw-r--r-- | src/2015/day25/aoc.cpp | 49 |
2 files changed, 55 insertions, 1 deletions
diff --git a/src/2015/day25/README.md b/src/2015/day25/README.md index a79a355..28f5d1b 100644 --- a/src/2015/day25/README.md +++ b/src/2015/day25/README.md @@ -40,3 +40,10 @@ So, to find the second code (which ends up in row 2, column 1), start with the p "Now remember", the voice continues, "that's not even all of the first few numbers; for example, you're missing the one at 7,1 that would come before 6,2. But, it should be enough to let your-- oh, it's time for lunch! Bye!" The call disconnects. Santa looks nervous. Your puzzle input contains the message on the machine's console. What code do you give the machine? + +--- Part Two --- +The machine springs to life, then falls silent again. It beeps. "Insufficient fuel", the console reads. "Fifty stars are required before proceeding. One star is available." + +..."one star is available"? You check the fuel tank; sure enough, a lone star sits at the bottom, awaiting its friends. Looks like you need to provide 49 yourself. + +You have enough stars to . diff --git a/src/2015/day25/aoc.cpp b/src/2015/day25/aoc.cpp index dd622e9..9154c57 100644 --- a/src/2015/day25/aoc.cpp +++ b/src/2015/day25/aoc.cpp @@ -2,5 +2,52 @@ namespace aoc2015 { -std::pair<int64_t, int64_t> day25(line_view lv) { return {0, 0}; } +/* So, to find the second code (which ends up in row 2, column 1), + * start with the previous value, 20151125. + * Multiply it by 252533 to get 5088824049625. Then, divide that by 33554393, + * which leaves a remainder of 31916031. That remainder is the second code. + */ +int64_t code_gen(int64_t code) { + code *= 252533; + code %= 33554393; + return code; +} + +// n = 0 .. +int64_t code_gen(int64_t code, size_t n) { + while (n-- > 0) { + code = code_gen(code); + } + return code; +} + +// n = 1 .. +int64_t total_number_by(size_t n) { + int64_t t{0}; + for (size_t i = 1; i <= n; i++) { + t += i; + } + return t; +} + +size_t row_number(int64_t r, int64_t c) { return r + c - 1; } + +int64_t code_by(size_t r, size_t c) { + size_t row = row_number(r, c); + int64_t total = total_number_by(row - 1); + + for (size_t x = row; x >= 1; x--) { + if (x == r) { + return code_gen(20151125, total); + } + total += 1; + } + return 0; +} + +// Enter the code at row 2947, column 3029. +std::pair<int64_t, int64_t> day25(line_view lv) { + return {code_by(2947, 3029), 0}; +} + } // namespace aoc2015 |