diff options
Diffstat (limited to 'src/Day03.kt')
-rw-r--r-- | src/Day03.kt | 71 |
1 files changed, 51 insertions, 20 deletions
diff --git a/src/Day03.kt b/src/Day03.kt index c64da47..94b1bf4 100644 --- a/src/Day03.kt +++ b/src/Day03.kt @@ -1,30 +1,61 @@ -fun main() { - fun addLists(l1: List<Int>, l2: List<Int>): List<Int> = l1.zip(l2).map { it.first + it.second } - - fun valueOfBits(bitList: List<Int>): Int = bitList.reduce { acc, bit -> acc * 2 + bit } +/** + * Add two lists element by element. + * @param l1 first list + * @param l2 second list + * @return a new list, where each element at index `i` is equal to `l1.get(i) + l2.get(i)` + */ +fun addLists(l1: List<Int>, l2: List<Int>): List<Int> = l1.zip(l2).map { it.first + it.second } - fun invertBits(bitList: List<Int>): List<Int> = bitList.map { bit -> 1 - bit } +/** + * Returns the decimal value of a binary number represented as a list of bits. + * @param bitList list of bits + * @return decimal value of binary number + */ +fun valueOfBits(bitList: List<Int>): Int = bitList.reduce { acc, bit -> acc * 2 + bit } - fun mostCommonBits(input: List<List<Int>>): List<Int> = - input - .reduce(::addLists) - .map { bit -> if (bit.toDouble() / input.size >= 0.5) 1 else 0 } +/** + * Invert all bits of a binary number. + * @param bitList list of bits + * @return list of bits, where each bit of [bitList] is flipped + */ +fun invertBits(bitList: List<Int>): List<Int> = bitList.map { bit -> 1 - bit } - fun selectByBitCriteria( - input: List<List<Int>>, - comparisonCriteria: (currentList: List<List<Int>>) -> List<Int> - ): List<Int>? { - var list = input - var index = 0 +/** + * Given a list of binary numbers (represented as a list of bits) return a binary number, + * where each bit has the value most common at that position among the numbers in the list. + * @param input list of lists of bits + * @return list of bits, where each bit has the most common value in the corresponding position of all numbers in the list + */ +fun mostCommonBits(input: List<List<Int>>): List<Int> = + input + .reduce(::addLists) + .map { bit -> if (bit.toDouble() / input.size >= 0.5) 1 else 0 } - while (list.size > 1 && index < list[0].size) { - list = list.filter { e -> e[index] == comparisonCriteria(list)[index] } - index += 1 - } +/** + * Find a binary number from a list, by filtering out values until one remains. + * While the list has more than one number, remove numbers having a different bit + * value at current position (starting at 0, increased by 1 after each filtering) + * then the value at corresponding position in the `comparisonCriteria(currentList)` list. + * @param input list used to search for the value + * @param comparisonCriteria function returning a binary number used to compare with others for filtering + * @return found binary number represented as a list of bits + */ +fun selectByBitCriteria( + input: List<List<Int>>, + comparisonCriteria: (currentList: List<List<Int>>) -> List<Int> +): List<Int>? { + var list = input + var index = 0 - return list.getOrNull(0) + while (list.size > 1 && index < list[0].size) { + list = list.filter { e -> e[index] == comparisonCriteria(list)[index] } + index += 1 } + return list.getOrNull(0) +} + +fun main() { fun part1(input: List<List<Int>>): Int = mostCommonBits(input) .let { gammaBits -> |